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Quantitative Aptitude | Questions

Permutations and Combinations questions with solutions

Permutations and Combinations is a Quantitative Aptitude topic for competitive exams. It appears across bank and railway exams. This page has 9 solved permutations and combinations questions written to the official pattern, with a worked solution under each.

9 questionsQuantitative Aptitude
  1. Question 1Easy

    In how many ways can 3 people be chosen from a group of 8?

    • A.42
    • B.70
    • C.62
    • D.50
    • E.56Correct
    Show solution

    This is 8C3 = 8!/(3!×5!) = 56.

  2. Question 2Moderate

    In how many ways can 3 people be chosen from a group of 5?

    • A.5
    • B.3
    • C.17
    • D.15
    • E.10Correct
    Show solution

    This is 5C3 = 5!/(3!×2!) = 10.

  3. Question 3Moderate

    In how many ways can 3 people be chosen from a group of 7?

    • A.19
    • B.31
    • C.39
    • D.35Correct
    • E.51
    Show solution

    This is 7C3 = 7!/(3!×4!) = 35.

  4. Question 4Moderate

    In how many ways can 2 people be chosen from a group of 6?

    • A.21
    • B.15Correct
    • C.8
    • D.22
    • E.9
    Show solution

    This is 6C2 = 6!/(2!×4!) = 15.

  5. Question 5Moderate

    In how many ways can 2 people be chosen from a group of 9?

    • A.22
    • B.20
    • C.52
    • D.50
    • E.36Correct
    Show solution

    This is 9C2 = 9!/(2!×7!) = 36.

  6. Question 6Moderate

    In how many ways can 2 people be chosen from a group of 5?

    • A.10Correct
    • B.18
    • C.16
    • D.2
    • E.4
    Show solution

    This is 5C2 = 5!/(2!×3!) = 10.

  7. Question 7Moderate

    In how many ways can 2 people be chosen from a group of 8?

    • A.30
    • B.22
    • C.34
    • D.28Correct
    • E.26
    Show solution

    This is 8C2 = 8!/(2!×6!) = 28.

  8. Question 8Hard

    In how many ways can 3 people be chosen from a group of 6?

    • A.32
    • B.4
    • C.36
    • D.20Correct
    • E.8
    Show solution

    This is 6C3 = 6!/(3!×3!) = 20.

  9. Question 9Hard

    In how many ways can 3 people be chosen from a group of 9?

    • A.100
    • B.84Correct
    • C.68
    • D.78
    • E.90
    Show solution

    This is 9C3 = 9!/(3!×6!) = 84.

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Frequently asked questions

How many Permutations and Combinations questions are here?

This page shows 9 worked permutations and combinations questions from a bank of 9, spanning 1 easy, 6 moderate and 2 hard. The full set is available to attempt in the timed-free practice drills and the mock tests.

Which exams ask Permutations and Combinations questions?

Permutations and Combinations is a standard Quantitative Aptitude topic across bank and railway recruitment exams.

Are these Permutations and Combinations questions free, and are the answers reliable?

Yes. Every question is free, written in-house to the exam pattern rather than copied from a real paper, and the numeric answer keys are recomputed independently at build time — a wrong key fails the build rather than reaching you.